Simplify Path @ LeetCode (Python)
kitt
posted @ 2014年2月20日 21:03
in LeetCode
, 1724 阅读
Use a stack.
class Solution:
# @param path, a string
# @return a string
def simplifyPath(self, path):
stack = ['/']
for i in path.strip('/').split('/'):
if i == '.' or i == '': continue
if i == '..':
if len(stack) > 1: stack.pop()
else:
stack.append(i + '/')
return ''.join(stack).rstrip('/') if len(stack) > 1 else ''.join(stack)
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