Clone Graph @ LeetCode (Python)
kitt
posted @ 2014年3月15日 16:36
in LeetCode
, 2820 阅读
BFS和DFS应该都可以, 我用了BFS。根据一楼评论, 用了一个dictionary来记录所有新生成的node, 并且测试数据中有...#3,4,4#...的情况, 所以只要node一入队，就认为是visited. 而不是node出队时才认为是visited (这种情况下node 4会被访问两次)。
# Definition for a undirected graph node
# class UndirectedGraphNode:
# def __init__(self, x):
# self.label = x
# self.neighbors = []
class Solution:
# @param node, a undirected graph node
# @return a undirected graph node
def cloneGraph(self, node):
if node == None: return None
newNodes = {node.label : UndirectedGraphNode(node.label)}
q = collections.deque(); q.append(node)
newQ = collections.deque(); newQ.append(newNodes[node.label])
visited = set([node]) # A node will be visited as long as it's enqueued
while q:
currNode = q.popleft(); newCurrNode = newQ.popleft()
for n in currNode.neighbors:
if n.label not in newNodes:
newNodes[n.label] = UndirectedGraphNode(n.label)
newCurrNode.neighbors.append(newNodes[n.label])
if n not in visited:
q.append(n); newQ.append(newNodes[n.label])
visited.add(n) # A node will be visited as long as it's enqueued
return newNodes[node.label]
2014年3月31日 17:18
请问queue里面会有重复的节点出现吗？感觉复制邻居的时候都是创建新节点，没有使用之前创建的新节点。
举例子：这里有123三个节点
1,2,3 #2,3#3
访问1的时候会把2，3入队；队列2,3
访问2：队列3,3 <------队列中有重复节点，而且都会再访问一次。
访问3：队列3
2014年4月01日 14:19
@有问题: 已更新，多谢提醒～
2014年4月01日 14:23
@有问题: 速度确实快了, 原来要640ms, 现在440ms
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